## General Discussion > Counterspace

Isn't it just like the projective counterspace, a la RST2 ?

Doug wrote :
"We can easily see this when we diagram the two, reciprocal, reference systems:

Reference system of discrete RNs: -∞ <——————-> 0 <———————> +∞
Reference system of continuous RNs: -0 <——————-> 1 <———————> +0

Clearly, one is the reciprocal of the other."

Horace

July 30, 2007 | Horace

Hi Horace,

It's just like the four regions of Larson's RST. The continuous range, from -0 to 1, is the time-space region, where 1 is c-speed, and the continuous range, from 0 to 1, is the space-time region.

However, the continuous range of values do not exist independently of the discrete values. In other words, there is no continuous range of values from -0 to 1, unless there is a discrete value of -1 to establish it. It is the same for the inverse values. There is no continuous range of values from 0 to 1, unless there is a discrete value of 1 to establish it.

The -1 and 1 are unit speed-displacements, measured over 2 units of space|time progression. In the -1 case, the space "direction" reversals create it. The space unit displacement ratio is ds|dt = 1|2 = -1 unit of time-displacement, where one unit of the space progression, of every two units of space|time progression, is an inward unit.

In the case of the inverse of this, the 1 case, the time unit displacement ratio is ds|dt = 2|1 = 1 unit of space-displacement, where one unit of the time progression, of every two units of time|space progression, is an inward unit.

When the -1 (SUDR) and the 1 (TUDR) units are joined together, then each contributes two units of space|time progression to the combination, for a total of four units of progression.

The equation of the S|T combination is:

ds|dt = 1|2 + 1|1 + 2|1 = 4|4 num,

where num is short for "natural units of motion," and where the middle term is composed of the inward space and inward time units of the SUDR and TUDR. Hences, the net outward space|time progression of this SUDR|TUDR (S|T) combo unit is

ds|dt = 1|2 + 2|1 = 3|3 num,

while its net inward space|time progression is

ds|dt = 1|1 num.

However, even though these two net progressions are in opposing directions, the difference,

ds|dt = 2|2 = 1|1 num,

is still unit speed. Therefore, the S|T unit "propagates" at c-speed relative to individual SUDRs and TUDRs.

Nevertheless, each S|T unit consists of a unique spatial location (SUDR), in the progression, and an associated unique temporal location (TUDR), in the progression. Therefore, it's possible that the spacetime locations, in one S|T unit, can approach the spacetime locations of another S|T unit, but if they do they can combine in two different ways.

One way is SUDR to SUDR and TUDR to TUDR. These combos constitute bosons. The other way is SUDR to TUDR and TUDR to SUDR, but unless the number of S|T units combining in this way is three, the combo is a boson type result, where the space|time progression of a SUDR cancels that of TUDR and vice versa.

However, when the respective UDRs of three S|T units combine, so that the SUDR|TUDR components of one S|T unit combine with the inverse component of two others, forming a triangle configuration, then the distance between them is less than one unit of motion at the connections.

In other words, the time and space regions of the RST exist at the apexes of the S|T triplets, where the distance between the space locations of two adjacent SUDRs is less than one unit, and the time locations of the associated TUDRs is also less than one unit.

This is the region, inside unit distance, that corresponds to the counterspace region of the RS2 concept, I do believe.

Doug

July 31, 2007 | Doug

http://www.rs2theory.com/core/playPresentation.php?id=6&slide=3

Thanks for the reply. My question was prompted by the great similarity between the URL above, and your qote below.

Horace

Doug wrote :
"We can easily see this when we diagram the two, reciprocal, reference systems:

Reference system of discrete RNs: -∞ <——————-> 0 <———————> +∞
Reference system of continuous RNs: -0 <——————-> 1 <———————> +0

Clearly, one is the reciprocal of the other."

August 3, 2007 | Horace

Horace,

I'm not sure, because I don't understand what he's trying to say, in that slide, to tell you the truth.

Doug

August 4, 2007 | Doug

Doug,

"Did you try to click back and forward to see the other slides? Maybe this one was too much out of context.

It's really worth to see the similarities to your recent conclusions.

Bruce wrote:
"From Space: absolute locations in space are discrete, locations in counterspace are wavefunctions (continuous).

From Counterspace: a single wave is discrete in counterspace, locations in space are non-local (continuous)."

Horace

August 4, 2007 | Horace

Thanks Horace. I didn't, but I will. It'll take me a while to get to it. Got my hands full, but I'll look into it as soon as I get a chance.

August 6, 2007 | Doug

Did you ever get to it ?

Horace

January 28, 2008 | Horace

No, the link is broken on the new RS2 site. Can you find the new url for me?

January 29, 2008 | Doug

I think I was refering to the presentation below: